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7. The length of a rectangle is two times its width. If the perimeter of the
rectangle can be no more than 54 units, what are the possible widths of
the rectangle?

Answer must be an inequalty, like x is less than or equal to 10 or something.​

Respuesta :

aamtally

Answer:

length= 2w

width=w

Step-by-step explanation:

2w + w≥ 54

Danli2360380

Answer:

The inequality should be x [tex]\leq[/tex] 9

Step-by-step explanation:

x + 2x + x + 2x [tex]\leq[/tex] 54 you should change it to 6x [tex]\leq[/tex] 54 and divide 54 by 6 and you should get x [tex]\leq[/tex] 9

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