Answer:
2500 miles
Step-by-step explanation:
Since the distance of the car varies inversely with its speed, the distance can be expressed as follows:
[tex] d = \frac{g*a}{s} [/tex] (1)
Where:
d: is the distance
s: is the speed of the car
g: is the gallons of fuel
a: is a constant of proportionality
With the first values, we can find the constant a.
We have:
d = 300 milles
s = 50 mph
g = 10 gallons
Hence, a is:
[tex] a = \frac{d*s}{g} = \frac{300 m*500 m/h}{10 g} = 15000 m^{2}g^{-1}h^{-1} [/tex]
Now, we can find the distance that the car can travel on 10 gallons of fuel at 60 mph:
[tex] d = \frac{g*a}{s} = \frac{10 g*15000 m^{2}g^{-1}h^{-1}}{60 m/h} = 2500 m [/tex]
Therefore, the car can travel 2500 miles on 10 gallons of fuel at 60 mph.
I hope it helps you!
Answer:
250 miles
Step-by-step explanation:
According to the question, The distance a car can travel on a certain amount of fuel varies inversely with its speed. If a car traveling 50 mph can travel 300 miles on 10 gallons of fuel and we are now asked to know how far the car could travel on 10 gallons of fuel at 60 mph.
----Distance is inversely proportional to the speed of the car
D = k/s
Where k is the constant
D = distance and S = speed
For every 10 gallons of fuel,the car travels at a speed of 50mph and a distance of 300 miles
300 =k/50
K = 1500
And we are now asked to find the distance of the car if the speed is 60mph
D = k/s
D = 1500/60
D = 250 miles
