contestada

4.00 L of a gas is known to contain 0.975 mol. If the amount of gas is increased to 3.80 mol, what new volume will result?

Respuesta :

The new volume is 15.59L

Explanation:

Given:

Initial volume, V₁ = 4L

Initial number of moles, n₁ = 0.975 mol

Final number of moles, n₂ = 3.8 mol

New volume, V₂ = ?

According to Avogadro's law:

[tex]\frac{V_1}{n_1} = \frac{V_2}{n_2}[/tex]

Substituting the values we get:

[tex]\frac{4}{0.975} = \frac{V_2}{3.8} \\\\V_2 = \frac{3.8 X 4}{0.975} \\\\V_2 = 15.59 L[/tex]

Therefore, the new volume is 15.59L