Answer:
[tex]\large \boxed{x = \sqrt{164}}[/tex]
Step-by-step explanation:
We have a right triangle, so we can use Pythagoras' Theorem:
The square of the hypotenuse equals the sum of the squares of the other two sides.
[tex]\begin{array}{rcl}x^{2}&=& 8^{2} + 10^{2}\\& = & 64 + 100\\x^{2} & = & 164\\\end{array}\\\large \boxed{\mathbf{ x = \sqrt{164}}}[/tex]
