contestada

Consider the following reaction: CO(g)+2H2(g) <--> CH3OH(g).
An equilibrium mixture of this reaction at a certain temperature was found to have
[CO]=0.115M, [H2]=0.116M, and [CH3OH]=0.190M. What is the value of the equilibrium constant (Kc) at this temperature?

Respuesta :

Answer:

123 is the equilibrium constant for the reaction.

Explanation:

[tex]CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)[/tex]

Equilibrium concentration of reactants :

[tex][CO]=0.115 M,[H_2]=0.116 M[/tex]

Equilibrium concentration of products:

[tex][CH_3OH]=0.190 M[/tex]

The expression of an equilibrium constant is given by :

[tex]K_c=\frac{[CH_3OH]}{[CO][H_2]^2}[/tex]

[tex]K_c=\frac{0.190 M}{0.115 M\times (0.116 M)^2}[/tex]

[tex]K_c=122.78 \approx 123[/tex]

123 is the equilibrium constant for the reaction.

Otras preguntas