Answer:
The magnetic field strength is 0.29 T.
Explanation:
Given that,
Length of current-carrying wire, L = 52 cm = 0.52 m
Current, I = 15 A
Magnetic force, F = 2.3 N
We need to find the magnetic field strength. We know that the magnetic force is given by :
[tex]F=ILB[/tex]
B is magnetic field strength
[tex]B=\dfrac{F}{IL}\\\\B=\dfrac{2.3}{0.52\times 15}\\\\B=0.29\ T[/tex]
So, the magnetic field strength is 0.29 T.
