Respuesta :
Answer:
Angular frequency is 20 rad/s.
Explanation:
Given that,
A block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s) is given by :
[tex]x(t)=1.5\cos(20\ t)[/tex].....(1)
The general equation of oscillating particle is given by :
[tex]x(t)=A\cos(\omega t)[/tex].......(2)
Compare equation (1) and (2) we get :
[tex]\omega=20\ rad/s[/tex]
So, the angular frequency of the oscillation is 20 rad/s.
The angular frequency ( ω ω ) of oscillation should be considered as the 20 rad/s.
Calculation of the angular frequency:
Since
A block should be attached to an oscillating spring.
The function below shows its position (cm) vs. time (s) should be provided by
x(t) = 15cos(20t) ....(1)
here, general equation of oscillating particle should be
x(t) = Acos(wt) ....2
So if we compare these two equations so it should be 20 rad/s
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