Answer:
theoretical fracture strength is 9916.58 MPa
Explanation:
given data
surface crack of length L = 0.26 mm
radius of curvature r = 0.004 mm
stress So = 1230 MPa
solution
we get here theoretical fracture strength S that is express as
S = [tex]S_{0} \times \sqrt{\frac{L}{r} }[/tex] .................1
here So is stress and L is length and r is radius
put here value and we get
S = [tex]1230 \times \sqrt{\frac{0.26}{0.004} }[/tex]
solve it we get
S = 9916.58 MPa
so theoretical fracture strength is 9916.58 MPa