Answer:
0.63
Explanation:
We are given that
Radius of earth,[tex]R_E=6370 km[/tex]
Radius of orbit A,[tex]R_A=7590+6370=13960 km[/tex]
Radius of orbit B,[tex]R_B=6370+15800=22170 km[/tex]
We have to find the ratio of the potential energy of satellite B to that of satellite A in orbit.
Potential energy of orbit A=[tex]U_A=-\frac{GM}{R_A}=-\frac{GM}{13960}[/tex]
Potential energy of orbit B=[tex]U_B=-\frac{GM}{R_B}=-\frac{GM}{22170}[/tex]
[tex]\frac{U_B}{U_A}=\frac{13960}{22170}=0.63[/tex]
Hence,the ratio of the potential energy of satellite B to that of satellite A in orbit=0.63
