Answer: 22.8 grams
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} NaCl=\frac{58g}{58.5g/mol}=0.99moles[/tex]
The balanced chemical reaction is :
[tex]2Na+Cl_2\rightarrow 2NaCl[/tex]
According to stoichiometry :
As 2 moles of [tex]NaCl[/tex] is produced by = 2 moles of [tex]Na[/tex]
Thus 0.99 moles of [tex]NaCl[/tex] is produced by =[tex]\frac{2}{2}\times 0.99=0.99moles[/tex] of [tex]Na[/tex]
Mass of [tex]Na=moles\times {\text {Molar mass}}=0.99moles\times 23g/mol=22.8g[/tex]
Thus 22.8 g of [tex]Na[/tex] is reacted.
