Answer:
Mass of banana is [tex]1.12[/tex] Kg
Explanation:
Step 1: Determine the equation of speed of an object moving in an harmonic motion
Speed of moving in an harmonic motion is given by
[tex]v = \sqrt{\frac{k}{m} (A^2 -x^2)} \\[/tex]
Here, v represents the speed of the object in harmonic motion, k is the springs constant, m is the mass of the object, A is the amplitude, and x is the position.
In this question , [tex]x = 0[/tex] because only at this position maximum speed occurs
So the simplified equation becomes -
[tex]v = \sqrt{(\frac{k}{m} * A)}[/tex]
OR
[tex]m = \frac{kA^2}{v_(max)^2}[/tex]
Substituting the given values in above equation we get -
Assume spring constant is [tex]16[/tex]N/m
[tex]m = \frac{16 * 0.14}{2} \\m = 1.12[/tex]
Mass of banana is [tex]1.12[/tex] Kg
