Answer:
The car is going up at a speed of 22.5 mph
Step-by-step explanation:
In this question, we are asked to calculate the speed of a moving car which started moving at an initial velocity for a specific period of time.
To calculate this, we use one of the basic equations of motion;
v = u + at
Where v is the final velocity, u is the initial velocity and t is the time
From the question, we can identify the parameters as follows;
v = ?
u = 10mph
a = 2.5t mph per second for 5 seconds.
Hence a here would be 2.5 * 5 = 12.5
Now, let’s put these values in the equation
v = 10 + 12.5
v = 22.5 mph
Answer:
22.5 mph
Step-by-step explanation:
According to the question, a car is moving with an initial velocity of 10 mph accelerates at the rate of a(t)=2.5t mph per second for 5 seconds and we are asked to find out how fast is the car going when the 5 seconds are up?
The formula to be applied here so as to derive our answer is
v = u + at
Where v is the final velocity, u is the initial velocity,acceleration and t is the time
V = ???
U = 10
A = 2.5t ≈ 2.5 × 5 = 12.
T = 5
10 + 12.5 = 22.5 mph
