Respuesta :

bhavya2vemuri

Answer:

(x+10) (x+3)

Explanation:

1) this quadratic equation is in the form of: ax^2+bx+c

where we need to figure out what*what=c(30)

and what+what=13(b)

factors of 30:  -1,-30  1,30  2,15  -2,-15  3,10  -3,-10  5,6   -5,-6

factors of 30 which equal 13:    3,10

lets substitute 3 and 10 in lace of 13x to factor by grouping:

x^2+3x+10x+30

make two sets:

set a) x^2+3x

set b) 10x+30

the GCF in set a is "x":

x(x+3)

The Gcf in set b is 10:

10(x+3)

now combine the terms outside the parantheses:

(x+10)(x+3)=0

Hope this helps!

sunshine4357

Answer:

so you need to use the box method. see attachment below.

Explanation:

so you put the squared number in the top left box

then x value in the middle circle

then the other number in the bottom right box

then, you decide how you get x^2 which is x times x, so you put an x on either side of the x corner

then you decide what time what will equal 30, but ALSO add up to 13

in this case it was 3 and 10, because 3x10 is 30 and 3+10 is 13

then multiply the x times 3 and 10 to fill in the other two boxes

hope this helped!

Ver imagen sunshine4357

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