Respuesta :
Given a quadratic equation [tex]y=ax^2+bx+c[/tex], the x coordinate of the minumum/maximum is given by
[tex]x=-\dfrac{b}{2a}[/tex]
So, in your case, the x coordinate of the minimum is
[tex]x=-\dfrac{-4}{2}=2[/tex]
Given a quadratic equation [tex]y=ax^2+bx+c[/tex], the x coordinate of the minumum/maximum is given by
[tex]x=-\dfrac{b}{2a}[/tex]
So, in your case, the x coordinate of the minimum is
[tex]x=-\dfrac{-4}{2}=2[/tex]