Answer:
Answer:
(a) 0.428 m/s
(b) 0.232 m/s
Explanation:
mass, m = 4 kg
initial velocity, u = 4 m/s at 45° North of west = 4 ( - Cos 45 i + Sin 45 j)
[tex]\overrightarrow{u}=- 2.83 \widehat{i} + 2.83 \widehat{j}[/tex]
mass, M = 6 kg
initial velocity, U = 3 m/s at 30° South of east = 3 (Cos 30 i - Sin 30 j)
[tex]\overrightarrow{U}=2.6 \widehat{i} -1.5 \widehat{j}[/tex]
Let V is the velocity of centre of mass.
[tex]\overrightarrow{V}=\frac{m\times \overrightarrow{u}+M\times \overrightarrow{U}}{m + M}[/tex]
[tex]\overrightarrow{V}=\frac{4\times\left ( - 2.83 \widehat{i} +2.83 \widehat{j} \right )+ 6\times \left ( 2.6 \widehat{i} -1.5 \widehat{j} \right ) }{4 + 6}[/tex]
[tex]\overrightarrow{V}= 0.428 \widehat{i}+0.232 \widehat{j}[/tex]
(a)
east west component of velocity of centre of mass is 0.428 m/s
(b)
north south component of velocity of centre of mass is 0.232 m/s.
Explanation:
