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Assume that in man, brown eyes is dominant over blue eyes. A blue-eyed man, both of whose parents were brown-eyed, marries a brown-eyed woman whose father was blue-eyed and whose mother was brown-eyed. This man and this woman have a blue-eyed child. What are the genotypes of all the individuals mentioned?

Respuesta :

Answer:

Bb, Bb, bb, bb.

Explanation:

Lets Brown as B and Blue as b.

Brown eyes is dominant over blue eyes, so B is dominant over b.

A blue eyed man , as blue is recessive, so the genotype will be bb.

Women whose father was blue eyed and mother was brown, so she must be heterozygous, hence the genotype is Bb,

Now cross between this man(bb) and women(Bb).

bb×Bb

offspring = Bb, Bb, bb, bb.

(Bb)= Brown eyed

(bb)= blue eyed

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