Answer:
The critical angle for total internal reflection for the liquid when surrounded by air is 46.8 degrees.
Explanation:
Given that,
Angle of incidence, i = 38°
Angle of refraction, r = 26.5°
Firstly, we will find the refractive index of the liquid. It can be calculated using Snell's law as :
[tex]n=\dfrac{\sin i}{\sin r}\\\\n=\dfrac{\sin (38)}{\sin (26.5)}\\\\n=1.37[/tex]
The relation between refractive index and critical angle for total internal reflection for the liquid is given by :
[tex]\sin\theta_c=\dfrac{1}{n}\\\\\sin\theta_c=\dfrac{1}{1.37}\\\\\theta_c=46.8^{\circ}[/tex]
So, the critical angle for total internal reflection for the liquid when surrounded by air is 46.8 degrees.
