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An iron rod with a mass m slides on parallel horizontal gold rails, a distance L apart, and carries a current of I. The coefficient of kinetic friction between the rod and rails is μ. What vertical, uniform magnetic field is needed to keep the rod moving at a constant speed? (Enter the magnitude. Use any variable or symbol stated above along with the following as necessary: g

Respuesta :

Answer:

The expression is [tex]B=\frac{\mu mg}{IL}[/tex]

Explanation:

If the rod is move with constant velocity, the expression of the magnetic field is:

∑Fn = Fm - fk = 0

[tex]BILsin90-\mu n=0\\B=\frac{\mu n}{ILsin90} \\B=\frac{\mu mg}{IL}[/tex]

Where

B is the magnetic field

m is the mass

g is the gravity

I is the current

L is the distance

μ is the kinetic friction between the rod and rails

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