Respuesta :
Answer:
The bottom of the sea is 25 m below sea level.
Explanation:
Given data
Mass = 6.1 × [tex]10^{8} \ kg[/tex]
[tex]\rho_{sea} = 1020\ \frac{kg}{m^{3} }[/tex]
We know that Buoyant force on the tank is equal to gravity force of the tank.
[tex]F_B = F_g[/tex]
[tex](\rho_{Fluid}) (g) (V_{disp}) = m g[/tex]
[tex](\rho_{Fluid}) (V_{disp}) = m[/tex]
1020 × [tex]V_{disp}[/tex] = 6.1 × [tex]10^{8}[/tex]
[tex]V_{disp}[/tex] = 598039.21 [tex]m^{3}[/tex]
We know that
[tex]V_{disp}[/tex] = W × L × H
598039.21 = 300 × 80 × H
H = 25 m
Therefore the bottom of the sea is 25 m below sea level.
The bottom of the sea will be 25 m below sea level.Sea level is the intermediate surface level of the earth's coastal bodies of water,
What is sea level?
Sea level is the average surface level of one or more of the Earth's coastal bodies of water, from which heights like elevation may be determined.
The given data in the problem is;
m is the mass = 6.1 x10⁸ kg.
[tex]p_{sea}= 1 020 kg/m^3[/tex]
h is the height below sea level=?
The buoyant force is given by;
[tex]\rm F_B= F_g \\\\ \rho g v_{disp}=mg \\\\ \rm v_{disp}=\frac{6.1 \times 10^{8}}{1020} \\\\ \rm v_{disp}=598039.21 m^3[/tex]
The displaced volume is given as;
[tex]\rm V_{disp}= WLH \\\\ H = \frac{300 \times 80 }{5989039.21} \\\\ \rm H= 25 \ m[/tex]
Hence the bottom of the sea will be 25 m below sea level.Option d is correct.
To learn more about the sea level refer to the link;
https://brainly.com/question/25795078
