Respuesta :
Answer:
Please see explanation for the first part.
Explanation:
Part 1. Use Ampere's law and find the B field from a wire. If you set up a drawing, you would have a wire, with current 10 A. You can draw an amperian loop about the wire, with distance r = 0.002 m. Using Ampere's law:
[tex]\int\limits {B} \, ds[/tex] = mu * I (capitalized letter i, current through the amperian).
Mu naught is the permeability constant 4pi*10^-7. The ds component is an arc length which becomes r*dθ. The B field we assume is uniform and constant, so pull B out of the integral. Also since radius r is constant pull it out as well. Once done, then you will integrate dθ, from 0 to 2pi, a full circle. On the left side of the equation you will get B*2*pi*r. On the left, you can plug in the permeability constant and the current given (since the current through the amperian loop incorporates the total current).
Then isolate B, by dividing mu I by 2 pi r, to get your answer. I would recommend converting to SI units, or at least keep the units consistent.
a) The magnetic field strength at a point 2.0 mm radially from the center of the wire leading to the capacitor will be 5 ×10⁻⁷ T.
What is the strength of the induced magnetic field?
The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.
given
(I) is the current
d is the distance from the probe
B is the induced magnetic field
a) The magnetic field strength at a point 2.0 mm radially from the center of the wire leading to the capacitor will be 5 ×10⁻⁷ T.
For case 1 ,r= 2.0 mm
[tex]\rm B=\frac{\mu_0I}{2 \pi r} \\\\ \rm B=\frac{4\pi \times 10^{-7} \times 10.0 }{2 \pi (2..0\times 10^{-3})} \\\\ \rm B= 5 \times 10^{-7} \ T[/tex]
Hence the magnetic field strength at a point 2.0 mm radially from the center of the wire leading to the capacitor will be 5 ×10⁻⁷ T
(b) The magnetic field strength at a point of 2.0 mm radially from the center of the capacitor will be
The formula for the magnetic field is found as;
[tex]\rm B\ \frac{\mu_0 I r}{2 \pi R^2} \\\\ \rm B= \frac{(4 \pi \times 10^{-7} \times 10. \times 1 \times 10^{-2})}{2 \pi (2\times 10^{-2})^2} \\\\ B=5 \times 10^{-4} \ T[/tex]
Hence the magnetic field strength at a point of 2.0 mm radially from the center of the capacitor will be 5 × 10⁻⁴ T.
To learn more about the strength of induced magnetic field refer;
https://brainly.com/question/2248956
