Respuesta :
Answer: The [tex][OH-][/tex] concentration of the aluminum hydroxide solution is [tex]1.41\times 10^{-10}[/tex]
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pOH is calculated by taking negative logarithm of hydroxide ion concentration.
[tex]pOH=-\log [OH^-][/tex]
Putting in the values:
[tex]9.85=-\log[OH^-][/tex]
[tex][OH^-]=10^{-9.85}=1.41\times 10^{-10}[/tex]
Thus the [tex][OH-][/tex] concentration of the aluminum hydroxide solution is [tex]1.41\times 10^{-10}[/tex]
Answer: [tex][OH^{-}][/tex] of the aluminium hydroxide solution is [tex]1.41 \times 10^{-6}[/tex].
Explanation:
It is given that pH is 9.85 and the relation between pH and concentration of ions is as follows.
pH = [tex]-log [H^{+}][/tex]
9.85 = [tex]-log [H^{+}][/tex]
antilog (9.85) = [tex][H^{+}][/tex]
[tex][H^{+}] = 7.1 \times10^{-9}[/tex]
We also know that,
[tex][H^{+}][OH^{-}] = 10^{-14}[/tex]
[tex][OH^{-}] = \frac{10^{-14}}{7.1 \times 10^{-9}}[/tex]
= [tex]1.41 \times 10^{-6}[/tex]
Therefore, we can conclude that [tex][OH^{-}][/tex] of the aluminium hydroxide solution is [tex]1.41 \times 10^{-6}[/tex].
