Answer:
8.0*10^2
Explanation:
What volume (in milliliters) of a 15% (m/v) NaOH solution contains 120 g NaOH?
For 15% (m/v), the conversion factor can be 15%/100 mL or 100 mL/15%. In this case, 100 mL/15% is used because we need mL as our final expression. 100 mL/15% * 120 g NaOH= 800 mL NaOH. In scientific notation: 8.0*10² or 8.0e² mL NaOH.
The volume will be "[tex]8.0\times 10^2 \ mL \ solution[/tex]".
According to the question,
Mass of NaOH,
Concentration of NaOH solution,
Relationship used,
The volume of solution will be:
= [tex]120 \ g \ NaOH\times \frac{100 \ mL \ solution}{15 \ g \ NaOH}[/tex]
= [tex]800 \ mL \ solution[/tex]
= [tex]8.0\times 10^2 \ mL \ solution[/tex]
Thus the above answer is correct.
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