Answer:
[tex]z=\frac{0.503-0.48}{\sqrt{\frac{0.48(1-0.48)}{700}}}=1.218[/tex]
Now we can calculate the p value given by:
[tex]p_v =P(z>1.218)=0.1116[/tex]
Step-by-step explanation:
Information provided
n=700 represent the random sample selected
[tex]\hat p=0.503[/tex] estimated proportion of college enrollment
[tex]p_o=0.48[/tex] is the value that we want to test
z would represent the statistic
[tex]p_v[/tex] represent the p value (variable of interest)
System of hypothesis
we want to check if the true proportion for the college enrollment is higher thna 0.48, the system of hypothesis are:
Null hypothesis:[tex]p\leq 0.48[/tex]
Alternative hypothesis:[tex]p > 0.48[/tex]
The statistic is given by:
[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)
Replacing the info given we have:
[tex]z=\frac{0.503-0.48}{\sqrt{\frac{0.48(1-0.48)}{700}}}=1.218[/tex]
Now we can calculate the p value given by:
[tex]p_v =P(z>1.218)=0.1116[/tex]