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What volume of 0.500 M AgNO3 are needed to react with 100. mL of 0.400 M K2CrO4? 2 AgNO3(aq) + K2CrO4(aq) ➔ Ag2CrO4(s) + 2 KNO3(aq)

Respuesta :

Answer:

160 mL AgNO3 0.5 M

Explanation:

M= mol solute/L solution

mol solute= M * L solution

mol solute = (0.400 M * 0.1L) = 0.04 mol K2CrO4

2 mol AgNO3   -> 1 mol K2CrO4

                 x   ->    0.04 mol K2CrO4       x =0.08 mol AgNO3

L solution= mol solute/M

L solution= 0.08 mol AgNO3/0.500 M= 0.16 L= 160 mL

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