If the first term of an arithmetic sequence is 4 and the difference between con-
secutive terms is 5, what is the second term? The third term? The twelfth? The
eightieth? The nth?

Respuesta :

Answer:third term=14 twelfth term=59

Step-by-step explanation:

first term=a=4

Common difference=d=5

Second term=4+5=9

Third term=9+5=14

Using Tn=a+d(n-1)

T12=4+5(12-1)

T12=4+5x11

T12=4+55

T12=59

Twelveth term=59