Respuesta :

Since anything to the power of 0 is 1.

You get

8(1)+(-7)(1)
8-7
1

Answer:

1

Step-by-step explanation:

8(y^0) + (-7)(y^0)

Remove parentheses: (a)=a

= 8[tex]y^{0}[/tex]-7[tex]y^{0}[/tex]

Add similar elements: 8[tex]y^{0}[/tex]-7[tex]y^{0}[/tex]= [tex]y^{0}[/tex]

= [tex]y^{0}[/tex]

Apply rule [tex]a^{0}[/tex] = 1, [tex]\alpha \neq 0[/tex]

= 1