Answer:
a = 1; b = - 2; c = - 3
Explanation:
Given the quadratic equation:
x^2 - 2x - 3 = 0
The quadratic formular goes thus :
[-b ± √(b^2 - 4ac)] / 2a
From the general form of a quadratic equation:
Ax^2 + Bx + c = 0
Comparing the given quadratic equation with the formula:
Coefficient of x^2 = a = 1
Coefficient of x = b = -2
Constant c = -3
[-(-2) ± √((-2)^2 - 4(1)(-3)] / 2(1)
[2 ± √4 - (-12)] / 2
[2 ± √4 + 12] / 2
[2 ± √16] / 2
[2 ± 4] / 2
(2+4)/2 or (2-4)/2
6/2 or - 2/2
3 or - 1
