1096175
contestada

The solutions to \[2x^2 - 10x + 13 = 0\]are $a+bi$ and $a-bi,$ where $a$ and $b$ are positive. What is $a\cdot b?$[tex]The solutions to\[2x^2 - 10x + 13 = 0\]are $a+bi$ and $a-bi,$ where $a$ and $b$ are positive. What is $a\cdot b?$[/tex]

Respuesta :

Answer:

5/8

Step-by-step explanation:

(10 +/- √100-104)/4

(10 +/- 2i)/4

5/4 +/- 1/2i

5/4 * 1/2 = 5/8

Otras preguntas