Answer:
The output force of the piston is 105 N.
Explanation:
Given;
the area of the input piston, Aâ = 0.5 m²
the input force of the piston, Fâ = 15 N
the area of the output piston, Aâ = 3.5 m²
the output force of the piston, Fâ = ?
The pressure of the  hydraulic lift is given by;
[tex]P = \frac{F}{A}[/tex]
where;
P is the hydraulic pressure
F is the piston force
A is the area of the piston
[tex]P = \frac{F}{A} \\\\\frac{F_o}{A_o} = \frac{F_i}{A_i} \\\\F_o = \frac{F_iA_o}{A_i} \\\\F_o = \frac{15*3.5}{0.5} \\\\F_o = 105 \ N[/tex]
Therefore, Â the output force of the piston is 105 N.
