Calculate the size of side x to 1 decimal
place. Show your working.

Answer:
[tex]x=7.4[/tex] m and [tex]x=11.2[/tex] m
Step-by-step explanation:
To do these problems, we will need to use the Pythagorean Theorem.
Recall that it states [tex]a^2+b^2=c^2[/tex], where c is the longest side, the hypotenuse, of the triangle.
a) We have a triangle with side lengths 4.2 m and 6.1 m. These two sides correspond to a and b in this equation.
Now, we can plug these values into the equation and solve for c, which is x.
[tex](4.2)^2+(6.1)^2=x^2\\\\17.64+37.21=x^2\\\\x=\sqrt{54.85}\\\\x=7.406\\\\x=7.4[/tex]
b) We have a triangle with side lengths 5.1 m and 12.3 m. These sides correspond to a and c, so b will be x.
Now, we can plug these values into the equation and solve for x.
[tex](5.1)^2+x^2=(12.3)^2\\\\26.01+x^2=151.29\\\\x=\sqrt{151.29-26.01}\\\\x=\sqrt{125.28}\\\\x=11.193\\\\x=11.2[/tex]
Answer:
Step-by-step explanation:
Formula: A squared + B squared = C squared
For the first question:
4.2 squared = 17.64
6.1 squared = 37.21
17.64+37.21 = 54.85
C squared = 54.85
The square root of 54.85 = 7.4
So, x = 7.4 m
For the second question:
5.1 squared = 26.01
12.3 squared = 151.29
26.01 + 151.29 = 177.3
C squared = 177.3
The square root of 177.3 = 13.3
So, x = 13.3 m
Hope this helps!