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While riding a bike down a steep hill at 9ms you skid to a stop in 3.2 seconds. How far did the bike slide? Assume uniform acceleration.

Respuesta :

Answer:

24.30 m

Explanation:

v(final)=v(initial)+at

0 m/s= 9 m/s +a(3.2s)

a=-2.81 m/s^2

delta x= vt+ (1/2)at^2

=(9 m/s * 3.2 s)+ (.5* -2.81 m/s^2 * 3.2s)

=24.30 m

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