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Help!! plz!!
Write an equation that is parallel to 3x−2y=14 and passes through the point (-6, -11) in slope-intercept form.

Respuesta :

mhanifa

Answer:

  • y = 3/2x - 2

Step-by-step explanation:

Given line

  • 3x - 2y = 14

To find

  • Parallel line passing through the point (-6, -11)

Solution

Let's put the given line into slope-intercept form

  • 3x - 2y = 14
  • 2y = 3x - 14
  • y = 3/2x - 7

Parallel line has same slope, the equation of the parallel line is

  • y = 3/2x + b

Finding y-intercept using the point (-6, -11)

  • -11 = 3/2*(-6) + b
  • -11= -9 + b
  • b = -2

So the line is

  • y = 3/2x - 2
2304007

3*-6-2*-11=14

-18+22=14

22=14+18

10

uwu

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