Answer:
The cyclist takes 10 seconds to accelerate to 12 m/s.
Explanation:
Constant Acceleration Motion
It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
[tex]v_f=v_o+at[/tex]
Solving for t:
[tex]\displaystyle t=\frac{v_f-v_o}{a}[/tex]
The cyclist starts from rest (vo=0) and moves at vf=12 m/s with an acceleration [tex]a=1.2\ m/s^2[/tex].
Calculate the time:
[tex]\displaystyle t=\frac{12-0}{1.2}[/tex]
[tex]\displaystyle t=\frac{12}{1.2}[/tex]
[tex]\boxed{t=10\ sec}[/tex]
The cyclist takes 10 seconds to accelerate to 12 m/s.
