Answer:
a=3
Step-by-step explanation:
p(x)=x^2-x-6 and f(x)=x^2+3x-18
they have a common factor x=a
so, when they are devided by x-a leave 0 as the remainder ( by remainder theorem)
p(a) =0
f(a)=0
SO, p(a) =f(a)
a^2-a-6=a^2+3a-18
a^2-a^-a-3a= -18+6
-4a= - 12
a=3
