Answer:
[tex]2877kJ/mol[/tex]
Explanation:
Hello.
In this case, since the bond energy per C-H bond is 411 kJ/mol and we of course avoid the C-C bond since we are asked to compute the energy to break 7 C-H bonds, the 411 kJ/mol are multiplied by 7 as shown below:
[tex]7*411kJ/mol\\\\=2877kJ/mol[/tex]
Thus, we obtain the required bond dissociation energy. Note that propane CH₃-CH₂-CH₃ has seven C-H bonds; 3 from the first CH₃, two from the CH₂ and 3 from the last CH₃.
Best regards.
Bond dissociation energy is defined as the energy required to dissociate or break a bond to form two or more molecular fragments.
In the given molecule of propane, the energy required to break the seven C-H bonds is 2877 kJ/mol.
The bond dissociation energy for the highly stable bond will be very high. In the given bonds of carbon and hydrogen, we know that:
Each C-H bond has an energy of 411 kJ/mol.
To calculate the bond dissociation energy of 7 C-H bonds, we have:
1 C-H bonds = 411 kJ/mol
7 C-H bonds = 411 x 7
7 C-H bonds = 2877 kJ/mol
Therefore, the bond dissociation energy required to break the seven C-H bonds is 2877 kJ/mol.
To know more about bond dissociation energy, refer to the following link:
https://brainly.com/question/14460882
