Answer:
From 22.9 g of HF 0.575 moles of tin(II) fluoride are produced.
Explanation:
Given data:
Moles of tin(II) fluoride produced = ?
Mass of hydrogen fluoride react = 22.9 g
Solution:
Chemical equation:
SnO + 2HF → SnF₂ + H₂O
Number of moles of HF:
Number of moles = mass/ molar mass
Number of moles = 22.9 g/ 20 g/mol
Number of moles = 1.15 mol
Now we will compare the moles of SnF₂ with HF.
HF : SnF₂
2 : 1
1.15 : 1/2×1.15 = 0.575 mol
Thus, from 22.9 g of HF 0.575 moles of tin(II) fluoride are produced.
