The area of a parallelogram is the same as the area of a square. The base of the parallelogram is twice the length of its height. The side of the square is 2 less than the height of the parallelogram
Area of a parallelogram: a = base • height
Area of a square: a = (side)2
1. variable h = parallelogram height
2. square area + parallelogram area
3. equation: (h – 2)2 + (2h • h)
The area of a parallelogram is the same as the area of a square. The base of the parallelogram is twice the length of its height. The side of the square is 2 less than the height of the parallelogram
Area of a parallelogram: a = base • height
Area of a square: a = (side)2
1. variable h = parallelogram height
2. square area + parallelogram area
3. equation: (h – 2)2 + (2h • h)
Analyze Jasper’s work. What was his mistake?
A The variable should be the length of the square.
B The areas of the square and parallelogram are equal.
C The area of a square is 4(h – 2).
D The area of a parallelogram is 2h + h.
