Answer:
D, or [tex]\frac{-1}{16}[/tex]
Step-by-step explanation:
To add (or subtract) fractions, you need to have a common denominator.
You might notice that the 16 on the bottom is a multiple of 8.
8*2 as a matter of fact
If we multiply [tex]\frac{1}{8\\}[/tex] by 1, it doesn't do anything, it stays as 1/8
1 is the same thing as [tex]\frac{1}{1}[/tex] and is also the same as [tex]\frac{2}{2}[/tex]
If we multiply [tex]\frac{1}{8}[/tex] by [tex]\frac{2}{2}[/tex], we get a bigger fraction, which is [tex]\frac{2}{16}[/tex]
So, our problem can be re-written as [tex]\frac{2}{16}+(-\frac{3}{16} )[/tex]
To add (or subtract) fractions with common denominators, you keep the common denominator and add (or subtract) the numerator.
[tex]\frac{2}{16}+(-\frac{3}{16})=\frac{2-3}{16}=\frac{-1}{16}[/tex]
The last step is to see if our answer can be reduced.
A fraction can't be reduced if there is a prime number in either the numerator or the denominator.
There is a -1 in the numerator, which is prime, and therefore, the fraction can't be reduced.
