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Rectangle ABCD is congruent to rectangle HGJK.

Rectangles A B C D and H G J K are shown. The length of A B is 11 inches. The length of K H is 18 inches.

What is the area of rectangle ABCD?

square inches

Respuesta :

Answer:

It is 198

Step-by-step explanation:

(Width)(Height)

mutliply (11) times (18)

The area of rectangle ABCD is 198 square inches

The given parameters are:

[tex]\mathbf{AB = 11}[/tex]

[tex]\mathbf{KH = 18}[/tex]

Because the rectangles are congruent, then:

[tex]\mathbf{HG = AB = 11}[/tex]

[tex]\mathbf{KH = DA= 18}[/tex]

So, the area of rectangle ABCD is the product of side lengths AB and DA

So, we have:

[tex]\mathbf{Area = AB \times DA}[/tex]

Substitute values for AB and DA

[tex]\mathbf{Area = 11 \times 18}[/tex]

[tex]\mathbf{Area = 198}[/tex]

Hence, the area of rectangle ABCD is 198 square inches

Read more about areas at:

https://brainly.com/question/9655204