Answer:
102.58 cal.
Explanation:
Given data:
Mass of mercury = 622 g
Initial temperature = 37°C
Final temperature = 42°C
Specific heat capacity of mercury = 0.138 J/g.°C
Energy required = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 42°C - 37°C
ΔT = 5°C
Q = 622 g × 0.138 J/g.°C × 5°C
Q = 429.18 J
J to cal:
429.18 J × 1 cal /4.184 j
102.58 cal.
