Calculate the amount of heat (in kJ) required
to raise the temperature of 250 grams of water
from 30°C to 90°C. (The specific heat of water
is 4.18 J/g.°C.)
Answer in units of kJ.

Respuesta :

Answer:

=62.7 KJ

Explanation:

0.250x4.18x(90-30) = 62.7