Answer:
The ball will hit the ground 108.25 m down the field
Explanation:
To determine how far down the field the ball will hit the ground, that is the Range of the ball. From formula to calculate Range in projectile motion,
[tex]R = \frac{u^{2} sin2\theta }{g}[/tex]
Where R is the Range
u is the initial velocity
θ is the angle of projection
and g is acceleration due to gravity (Take g = 9.8 m/s²)
From the question,
Initial velocity, u = 35 m/s
Angle, θ = 60°
Putting these values into the equation, we get
[tex]R = \frac{35^{2} ( sin2(60)) }{9.8}[/tex]
[tex]R = \frac{1225 \times sin(120)}{9.8}[/tex]
[tex]R = \frac{1225 \times 0.8660}{9.8}[/tex]
[tex]R = \frac{1060.85}{9.8}[/tex]
[tex]R = 108.25 m[/tex]
Hence, the ball will hit the ground 108.25 m down the field.
