Water boils at 100 degrees celsius or 212 degrees fahrenheit. Water freezes at 0 degrees celsius or 32 degrees fahrenheit. If the weather forecaster says it will be 25 degrees celsius today. write and solve a linear equation to find what fahrenheit temperature this is.

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Answer:

given with two conditions: after 0 degrees Celsius, this is equal to 32 degrees Fahrenheit and after at 100 degrees Celsius, this is equal to 212 degrees Fahrenheit . We translate these into points, we have (0,32) and (100, 212). we get the slope of the points ((212-32)/100) or 9/5. we plug to the equation y-y1 = m (x-x1) where m is equal to 9/5. y-32 = 9/5 (x-0). Simplifying, we get y -32 = 9x/5 or equal to y = 9/5 x + 32 where x is degrees Celsius and y is degrees Fahrenheit.

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The given temperature is required in Fahrenheit.

The required temperature is 77 degrees Fahrenheit.

Let the x axis denote Celsius

and y axis denote Fahrenheit

The ordered pairs are [tex](100,212)[/tex] and [tex](0,32)[/tex]

The equation of the line will be

[tex]y-212=\dfrac{32-212}{0-100}(x-100)\\\Rightarrow y-212=1.8(x-100)\\\Rightarrow y-212=1.8x-180\\\Rightarrow y=1.8x+32[/tex]

The temperature is 25 degrees Celsius so [tex]x=25[/tex]

[tex]y=1.8\times 25+32\\\Rightarrow y=77[/tex]

The required temperature is 77 degrees Fahrenheit.

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