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06-10-2016
Mathematics

contestada

Answer is due in 1 hour!

Find an equation of the tangent line to the curve
y = 10x sin x
at the point (π/2, 5π).

Respuesta :

06-10-2016

y = 10x * sin(x)
y' = 10 * (x * cos(x) + sin(x))
x = pi/2
y' = 10 * ((pi/2) * cos(pi/2) + sin(pi/2)) = 10 * ((pi/2) * 0 + 1) = 10 * 1 = 10
y - 5pi = 10 * (x - (pi/2))
y - 5pi = 10x - 5pi
y = 10x

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