20.91 grams of ice can be melted
Q fusion = m x L
L = latent heat , kj/kg
m = mass, kg
Q = heat, kJ
Reaction :
H₂O(s)⇒H₂O(l)
Q = 6982.6 J=6.9826 kJ
L for ice = 3.34 x 10⁵ J/kg=334 kJ/kg
mass of ice :
[tex]\tt m=\dfrac{Q}{L}\\\\m=\dfrac{6.9826}{334}=0.020905~kg= 20.91~g[/tex]
