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There is a right triangle with sided of lenght 33, 56 and 65. Let x be the angle opposite the side of lenght 56.
A. Sin(x)=
B.Cos(x)=
C.Sin(2x)=
D.Sin(x/2)=

Respuesta :

evanrosario11

Answer:

sin  x  = 33/65, cos x = 56/65, tan x = 33/56,

sec x = 65/56, csc x = 65/33, cot x = 56/33

Step-by-step explanation:

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