Answer:
(6, 8)
Step-by-step explanation:
The rectangle ABCD has vertices at A(0,0), B(0,4), C(3,4) and D(3,0). The length of the sides is calculated using the distance formula:
[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Therefore:
[tex]|AB|=\sqrt{(0-0)^2+(4-0)^2}=4 \\\\|BC|=\sqrt{(3-0)^2+(4-4)^2}=3\\\\|CD|=\sqrt{(3-3)^2+(0-4)^2}=4\\\\|AD|=\sqrt{(3-0)^2+(0-0)^2}=3[/tex]
If the length of each side is doubled and point A stays the same. Let us assume that the new point of C is C'(x, y). Therefore C would be the midpoint of segment |AC'|:
[tex]3=\frac{0+x}{2}\\\\x=6\\\\4=\frac{0+y}{2}\\\\y=8[/tex]
Therefore C'=(6,8)
The new coordinate of point C would be (6, 8)
