Given:
2 ft³ of clay was mixed into 7 ft³ of soil containing 55% clay.
To find:
Clay content of the mixture.
Solution:
We have,
55% of soil is clay. So,
Clay in soil= 55% of soil
[tex]\text{Clay in soil}=\dfrac{55}{100}\times 7[/tex]
[tex]\text{Clay in soil}=\dfrac{385}{100} [/tex]
[tex]\text{Clay in soil}=3.85 [/tex]
2 ft³ of clay was mixed into the soil. So, the total clay content of the mixture is
[tex]2+3.85=5.85\text{ ft}^3[/tex]
Therefore, the clay continent in the mixture is 5.85 ft³.