Answer:
we get [tex]x^2=12-6\sqrt{3}[/tex]
Step-by-step explanation:
We are given: [tex]x=3-\sqrt{3}[/tex]
We need to find [tex]x^2[/tex]
Note: Since question is not clear, I am assuming that we need to find [tex]x^2[/tex]
Solving:
[tex]x=3-\sqrt{3} \\Taking \ square \ on \ both \ sides\\x^2=(3-\sqrt{3})^2\\[/tex]
We know that [tex](a-b)^2= a^2-2ab+b^2[/tex]
Using formula and simplifying
[tex]x^2=(3)^2-2(3)(\sqrt{3})+(\sqrt{3})^2\\x^2=9-6\sqrt{3} +3\\x^2=12-6\sqrt{3} \\[/tex]
So, we get [tex]x^2=12-6\sqrt{3}[/tex]
