Respuesta :
Answer:
±12.323
Step-by-step explanation:
A study by the department of education of a certain state was trying to determine the mean SAT scores of the graduating high school seniors. The study examined the scores of a random sample of 238 graduating seniors and found the mean score to be 493 with a standard deviation of 97. Calculate the margin of error using the given formula. How could the results of the survey be made more accurate?
The formula for margin of Error =
±z × Standard deviation/√n
We are not given the confidence interval but let us assume the confidence interval = 95%
Hence:
z score for 95% confidence interval = 1.96
Standard deviation = 97
n = random number of samples = 238
Margin of Error = ± 1.96 × 97/√238
Margin of Error = ±12.323
The margin of error using the given formula will be ±12.323.
What is the error?
An error is a mistaken or erroneous action. In some contexts, an error is interchangeable with a mistake.
The discrepancy between the calculated value and the correct value is referred to as an "error" in statistics.
Given data;
Confidence interval = 95%
z score for 95% confidence interval = 1.96
Standard deviation = 97
n is a random number of samples = 238
The margin of Error is found as;
E =±z × Standard deviation/√n
[tex]\rm E= +z \times \frac{\sigma}{\sqrt{n} }[/tex]
[tex]\rm E=\±1.96 \times \frac{97}{\sqrt{238} }\\\\ E=\±12.323 \[/tex]
Hence,the margin of error using the given formula will be ±12.323.
To learn more about the error refer to the link;
https://brainly.com/question/13286220
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